Determine the de Broglie 's wavelenght of electron emitted by a metal whose threshold frequency is `2.25xx10^(14)Hz` when exposed to visible radiation of wavelenght 500nm.

If the threshold frequency be 2 xx 10^14 Hz , the work function is

If the deBroglie wavelenght of an electron is equal to 10^-3 times the wavelenght of a photon of frequency 6xx 10 ^14 Hz ,then the calculate speed of electrone. Speed of light =3 xx 10^8 m//s Planck's constant =6.63 xx 10 ^(-34) J s Mass of electron =9.1 xx 10 ^(-31) kg

The threshold frequency for a metal is 10^(15) Hz. When light of wavelenght 4000 Å is made incident on it, then

The photoelectric threshold wavelength of a metal is 230 nm. Determine the maximum kinetic energy in joule and eV of the ejected electron from metal surface when it is exposed to a radiation of wavelength 180 nm. (Planck's constant h = 6.63 xx 10^-34 J-S, C = 3 xx 10^8 m//sec .)

The de Broglie wavelenght (lambda) associated with a photoelectron varies with the frequency (v) of the incident radiation as,[ v_(0) is threshold frequency]:

The de Broglie wavelenght (lambda) associated with a photoelectron varies with the frequency (v) of the incident radiation as,[ v_(0) is threshold frequency]:

The de Broglie wavelenght (lambda) associated with a photoelectron varies with the frequency (v) of the incident radiation as,[ v_(0) is threshold frequency]: