lim(x->pi/2){(1-sinx)tanx}...

`lim_(x->pi/2){(1-sinx)tanx}`

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Evaluate the following limits, if necessary use l' Hopital Rule : lim_(xto pi/2)(sinx)^(tanx)

lim_(xto pi/2)(sinx)/x=

lim_(xrarr(pi)/(2)) (1-sinx)tanx=

lim_(xrarr(pi)/(2)) (1-sinx)tanx=

lim_(xrarr(pi)/(2)) (1-sinx)tanx=

lim_(xrarr(pi)/(2)) (1-sinx)tanx=

The value lim_(xrarr pi//2)(sinx)^(tanx) , is

The value lim_(xrarr pi//2)(sinx)^(tanx) , is

Evaluate: lim_(x to pi/2) (sin x)^(tanx)

lim_(x to pi/2)(1-sinx)/(cosx) is equal to :

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