A quill tube contains a mercury column of length `19cm`. The length of air column is `24cm` when it is held veritcally. On inverting it with its open end downwards the length of air column will be
(atmospheric pressure `= 76cm` of `Hg`)

If above tube is held vertical with open end upward then find the length of air column (in cm).

In given figure, A uniform cylindrical tube closed at one end, contains a pallet of mercury 5cm long. When the tube is kept verticaly with the closed end downward, the length of the air column trapped is 30cm . Now the tube is inverted so that the closed end goes up find the new length of the air column trapped. atmospheric pressure =75cm of mercury. (Assume temperature remains constant in this process)

A uniform tube closed at one end, contains a pallet of mercury 4 cm long. When the tube is kept vertically with closed end upwards, the length of air column between closed end and mercury pallet is 10 cm. the tube is inverted so that open end becomes upwards. find the length of trapped air column (in cm) trapped. take atmospheric pressure 76 cm of Hg.

A uniform tube closed at one end, contains a pallet of mercury 4 cm long. When the tube is kept vertically with closed end upwards, the length of air column between closed end and mercury pallet is 10 cm. the tube is inverted so that open end becomes upwards. find the length of trapped air column (in cm) trapped. take atmospheric pressure 76 cm of Hg.

A Quill's tube of one metre is taken. A certain amount of ideal gas is trapped in it by a 20 cm length of Hg column. When the tube is held vertical with open end upwards, the length of the gas column is 50 cm. Find the pressure and length of the trapped gas, when the Quill's tube is kept in slanting position making 45^(@) with the vertical open and upwards. (Take atmospheric pressure as 76 cm of Hg and sqrt(2)=1.414) .