If `z=6(cos(2pi/7)+isin(2pi/7))` and `w=3(cos(5pi/7)+isin(5pi/7))` then what is the value of `z/w`

z=cos(pi/6)+isin(pi/6)=?

(cos(pi/6)+isin(pi/6))^7=?

z=5(cos((7pi)/6)+isin((7pi)/6))=?

7(cos((-5pi)/6)+isin((-5pi)/6))=?

If z = cos"" pi/4+ isin (pi/6) ,then

cos((2pi)/(7))+cos((4pi)/(7))+cos((6pi)/(7))=

"cos"(2pi)/(7) +"cos"(4pi)/(7)+"cos"(6pi)/(7)

Two of the three values of (-1)^(1//3) are cos(pi//3)+isin(pi//3),cos(5pi//3)+isin(5pi//3) .The third value is

the value of (cos pi)/(7)cos(2(pi)/(7))cos(3(pi)/(7)) is

The value of cos((2pi)/7)cos((4pi)/7)cos((6pi)/7) is