solve: `2/(2x+y)-1/(x-2y) +5/9=0` and `9/(2x+y) -6/(x-2y)+4=0`

Solve for x and y in the following question : 2/(x+2y)+1/(2x-y)+5/9=0, 9/(x+2y)+6/(2x-y)+4=0

Solve : (3)/(x + y ) + ( 2)/(x - y ) = 2 and (9)/(x + y ) - ( 4)/(x - y) = 1 .

Solve : (4x+y+9)dx+(x+2y+6)dy=0

The circles x^(2)+ y^(2) -6x-2y +9 = 0 and x^(2) + y^(2) =18 are such that they :

The circles x^(2)+ y^(2) -6x-2y +9 = 0 and x^(2) + y^(2) =18 are such that they :

Find the internal centre of similitude for the circles x^(2) + y^(2) + 6x - 2y + 1 =0 and x^(2) + y^(2) - 2x - 6y + 9 = 0 .

Find the equations to the common tangents of the circles x^(2)+y^(2)-2x-6y+9=0 and x^(2)+y^(2)+6x-2y+1=0

Solve for x and y : (x, y ne 0) (10)/(2x+y)+(3)/(2x-y)=3, (15)/(2x+y)+(9)/(2x-y)=6

Find the position of the circles x^(2)+y^(2)-2x-6y+9=0 and x^(2)+y^(2)+6x-2y+1=0 with respect to each other.r:

Show that the circles x^(2) + y^(2) + 2 x -6 y + 9 = 0 and x^(2) +y^(2) + 8x - 6y + 9 = 0 touch internally.