`(x+y)/(2)-(x-y)/(3)=8,(x+y)/(3)+(x-y)/(4)=4`

Solve the following equations by Elimination method : (x+y)/2 - (x-y)/3 =8 , (x+y)/3 + (x-y)/4 = 11 .

The following steps are involved in finding the value of x.y, if (3x + 4y)/(2x + 5y) = (4)/(3). Arrange them in sequential order from the first to the last. (A) 9x + 12 y = 8x + 20y (B) Given, (3x + 4y)/(2x + 5y) = (4)/(3) (C) (x)/(y) = 8 rArr x:y = 8:1 (D) (3x + 4y)3 = (2x + 5y)4 (E) x = 8y

Simplify : (x+y)^(4) - 4y(x+y)^(3) + 6y^(2)(x+y)^(2)-4y^(3)(x+y)+y^(4)

3-8 (2x-y) +4 (2x-y) ^ (2)

Solve : {:((34)/(3x+4y)+(15)/(3x-2y)=5),((25)/(3x-2y)-(8.50)/(3x+4y)=4.5):}

(x-4)(x-3)=(x-6)(x-5) (y-9)(y-3)= (y-4)(y-3)

The following are the steps involved in factorizing 64 x^(6) -y^(6) . Arrange them in sequential order (A) {(2x)^(3) + y^(3)} {(2x)^(3) - y^(3)} (B) (8x^(3))^(2) - (y^(3))^(2) (C) (8x^(3) + y^(3)) (8x^(3) -y^(3)) (D) (2x + y) (4x^(2) -2xy + y^(2)) (2x - y) (4x^(2) + 2xy + y^(2))

If (3x -4y) : (2x -3y) = (5x -6y) : (4x -5y) , find : x : y .

If the circle x^(2)+y^(2)=a^(2) intersects the hyperbola xy=c^(2) in four points P (x_(1) ,y_(1)) Q (x_(2), y_(2)) R (x_(3) ,y_(3)) S (x_(4) ,y_(4)) then 1) x_(1)+x_(2)+x_(3)+x_(4)=2c^(2) 2) y_(1)+y_(2)+y_(3)+y_(4)=0 3) x_(1)x_(2)x_(3)x_(4)=2c^(4) 4) y_(1)y_(2)y_(3)y_(4)=2c^(4)