The refracting angle of a glass prism is `30^@.` A ray is incident onto one of the faces perpendicular to it. Find the angle `delta` between the incident ray and the ray that leaves the prism. The refractive index of glass is `mu=1.5.`

The cross section of a glass prism mu=2 has the form of an isosceles right-angled triangle. It is submerged in a liquid of refractive index 1.2 . A ray is incident on to one of the equal faces perpendicularly. What is the angle between the direction of incident ray and the ray that emerges from the prism ?

The angle between the incident ray and the refracted ray of a prism is called angle of deviation.

An equilateral triangular prism is made of glass (mu = 1.5) . A ray of light is incident normally on one of the faces. The angle between the incident and emergent ray is

An equilateral triangular prism is made of glass (mu = 1.5) . A ray of light is incident normally on one of the faces. The angle between the incident and emergent ray is

The refractive angle of prism is A. A ray is incident normally on one of the refracting faces of a prism and emerges out. If D be the deviation of the ray then refractive index of the material of the prism is—

A ray of light is incident at 60^(@) on one face of a prism of angle 30^(@) and the emergent ray makes 30^(@) with the incident ray. The refractive index of the prism is

A ray of light is incident at 60^(@) on one face of a prism of angle 30^(@) and the emergent ray makes 30^(@) with the incident ray. The refractive index of the prism is

A ray of light is incident at 60^(@) on one face of a prism of angle 30^(@) and the emergent ray makes 30^(@) with the incident ray. The refractive index of the prism is

A ray of light is incident at 65^(@) on one face of a prism of angle of 30^(@) and the emergent ray makes 35^(@) with the incident ray. The refractive index of the prism is: