The centre of the circle,` r^2 = 2-4r costheta + 6rsintheta` is

The centre of the circle r^(2) - 4r (cos theta + sin theta) - 4 = 0 in cartesian coordinates is

The centre, radius of the circle r^(2) - 8 r cos (theta - (pi)/(3) ) + 12 =0 is

Answer the following:Find the centre and radius of the circle x=3-4sintheta and y=2-4costheta

A uniform circular plate of radius 2R has a circular hole of radius R cut out of it. The centre of the smaller circle is at a distance of R/3 from the centre of the larger circle. What is the position of the centre of mass of the plate?

The radii of two circles are R and r unit (R gtr). If the distance between the two centres of the circles be d unit, then prove that the length of their transversal common tangent =sqrt(d^(2) -(R+r)^(2)) unit.

If O is the centre of a circle with radius r and AB is a chord of the circle at a distance r/2 from O, then /_BAO=

If O is the centre of a circle with radius r and AB is a chord of the circle at a distance (r)/(2) from O, then /_BAO=