Home
Class 12
MATHS
In triangle A B C , the equation of side...

In triangle `A B C` , the equation of side `B C` is `x-y=0.` The circumcenter and orthocentre of triangle are (2, 3) and (5, 8), respectively. The equation of the circumcirle of the triangle is `x^2+y^2-4x+6y-27=0` `x^2+y^2-4x-6y-27=0` `x^2+y^2+4x+6y-27=0` `x^2+y^2+4x+6y-27=0`

Promotional Banner

Similar Questions

Explore conceptually related problems

In triangle A B C , the equation of side B C is x-y=0. The circumcenter and orthocentre of triangle are (2, 3) and (5, 8), respectively. The equation of the circumcirle of the triangle is a) x^2+y^2-4x+6y-27=0 b) x^2+y^2-4x-6y-27=0 c) x^2+y^2+4x-6y-27=0 d) x^2+y^2+4x+6y-27=0

In triangle A B C , the equation of side B C is x-y=0. The circumcenter and orthocentre of triangle are (2, 3) and (5, 8), respectively. The equation of the circumcirle of the triangle is a) x^2+y^2-4x+6y-27=0 b) x^2+y^2-4x-6y-27=0 c) x^2+y^2+4x-6y-27=0 d) x^2+y^2+4x+6y-27=0

In triangle ABC ,the equation of side BC is x-y=0. The circumcenter and orthocentre of triangle are (2,3) and (5,8), respectively. The equation of the circumcirle of the triangle is x^(2)+y^(2)-4x+6y-27=0x^(2)+y^(2)-4x-6y-27=0x^(2)+y^(2)+4x+6y-27=0x^(2)+y^(2)+4x+6y-27=0

Find the equation of the radical axis of the following circles. x^2+y^2-2x-4y-1=0 x^2+y^2-4x-6y+5=0

Find the equation of the radical axis of the following circles. x^2+y^2-2x-4y-1=0 x^2+y^2-4x-6y+5=0

The equation of the circle which cuts the three circles x^2+y^2-4x-6y+4=0, x^2+y^2-2x-8y+4=0, x^2+y^2-6x-6y+4=0 orthogonally is

The equation of the circle which cuts the three circles x^2+y^2-4x-6y+4=0, x^2+y^2-2x-8y+4=0, x^2+y^2-6x-6y+4=0 orthogonally is

Find the equation of the radical axis of the circles x^(2)+y^(2)-4x+6y-7=0,4(x^(2)+y^(2))+8x+12y-9=0

Find the equation of the common chord of the following pair of circles x^2+y^2-4x-4y+3=0 x^2+y^2-5x-6y+4=0