let `a_1,a_2,...a_n` be in A.P. wth common difference `pi/6`. if `seca_1seca_2+seca_2seca_3+....seca_(n-1)seca_n`=`k(tana_n-tana_1)`Find the value of k

If a_1, a_2, a_n are in A.P. with common difference d!=0 , then the sum of the series sind[seca_1seca_2+seca_2seca_3+....+s e ca_(n-1)seca_n] is : a. cos e ca_n-cos e ca b. cota_n-cota c. s e ca_n-s e ca d. t a na_n-t a na

If a_1, a_2, a_n are in A.P. with common difference d!=0 , then the sum of the series sind[seca_1seca_2+(sec)_2seca_3+....+s e ca_(n-1)(sec)_n] is : a.cos e ca_n-cos e ca b. cota_n-cota c. s e ca_n-s e ca d. t a na_n-t a na

If a_1, a_2, a_n are in A.P. with common difference d!=0 , then the sum of the series sind[seca_1seca_2+(sec)_2seca_3+....+s e ca_(n-1)(sec)_n] is : a. cos e ca_n-cos e ca b. cota_n-cota c. s e ca_n-s e ca d. t a na_n-t a na

If a_1,a_2,a_3,...,a_n are in AP and a_i ne (2k-1)pi/2 for all i , find the sum seca_1*seca_2+seca_2*seca_3+seca_3*seca_4+...+seca_(n-1)*seca_n .

If secA+tanA=p , then what is the values of sin A?

Prove: (secA+tanA-1)(secA-tanA+1)=2tanA

Prove: (secA+tanA-1)(secA-tanA+1)=2tanA

Find the value of (tanA+secA-1)cosA .

secA(1-sinA)(secA+tanA)=1