Reaction of `KMnO_(4)` in neutral or very weakly alkaline solution can be represented as:

Options

A. `MnO_(4)^(-)+2H_(2)O+3e^(-)toMnO_(2)+4OH^(-)`
B. `2MnO_(4)^(-)+2OH^(-)+2OH^(-)to2MnO_(4)^(2-)+1//2O_(2)+H_(2)O`.
C. `MnO_(4)^(-)+8H^(+)+5e^(-)toMn^(2+)+4H_(2)O`
D. `MnO_(4)^(-)+e^(-)toMnO_(4)^(2-)`.

Answer

A

Explanation

`MnO_(4)^(-)+3e^(-)+2H_(2)OtoMnO_(2)+4OH^-` (neutral/weak alkaline medium)