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When K(4)[Fe(CN)(6)] is added to FeCl(3)...

When `K_(4)[Fe(CN)_(6)]` is added to `FeCl_(3)` , the complex compound formed is:

A

`Fe_(3)[Fe(CN)_(6)]_(4)`

B

`Fe_(4)[Fe(CN)_(6)]_(3)`

C

`K_(2)Fe[Fe(CN)_(6)]`

D

`K_(2)Fe_(2)[Fe(CN)_(6)]_(2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`Fe^(3+)+[Fe(CN)_(6)]^(4-)toFe_(4)[Fe(CN)_(6)]_(3)` (prussian blue).
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In K_(4)Fe(CN)_(6)

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In K_(4)[Fe(CN)_(6)],Fe is in the form of

In K_4[Fe(CN)_6]Fe is in the form of

FeCl_3 + K_4[Fe(CN)_6] to ?

K_(3)[Fe(CN)_(6)]+FeCl_(3) to Fe[Fe(CN)_(6)]

Two solution (A)containing Fecl_(3)(aq) and(B) semipermeable membrance as shown below.If FeCl_(3) on reaction with K_(4)[Fe(CN)_(6)] ,produces blue colour of Fe_(4)[Fe(CN)_(6)] , the clue colour will be noticed in : |((A),,(B)),(FeCl_(3),,K_(4)[Fe(CN)_(6)])|

RESONANCE-D & F-BLOCK ELEMENTS & THEIR IMPORTANT COMPOUNDS -Only one option correct type
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