Which of the following is false for order of `-l` effect :

Options

A. `-Fgt-Clgt-Brgt-l`
B. `-C-=CHgt-CH=CH_(2)gt-CH_(2)-CH_(3)`
C. `-C-=CNgt-underset(O)underset(||)C-OH`
D. `-Phgt-C-=CH`

Answer

To determine which statement is false regarding the order of the -I (negative inductive) effect, we need to analyze the given options based on the principles of electronegativity and hybridization.

### Step-by-Step Solution:

1. **Understanding the -I Effect**: The -I effect refers to the electron-withdrawing effect of substituents due to their electronegativity. More electronegative atoms or groups exert a stronger -I effect.

2. **Analyzing Electronegativity**:
- The order of electronegativity for common elements is: F > O > N > C > H.
- Therefore, fluorine (F) has the strongest -I effect, followed by oxygen (O), nitrogen (N), and carbon (C).

3. **Considering Hybridization**:
- The hybridization of carbon affects its ability to withdraw electrons.
- The order of -I effect based on hybridization is: sp > sp2 > sp3. This means that sp hybridized carbon (which is more electronegative due to its higher s-character) has a stronger -I effect than sp2 or sp3 hybridized carbons.

4. **Evaluating the Options**:
- **Option 1**: If it states that F has the strongest -I effect, this is true.
- **Option 2**: If it states that sp hybridized carbon has a stronger -I effect than sp2 and sp3, this is also true.
- **Option 3**: If it mentions that a triple bond (which typically involves sp hybridized atoms) has a strong -I effect, this is true.
- **Option 4**: If it presents a different order that contradicts the established trends (for example, suggesting that sp3 has a stronger -I effect than sp), this would be false.

5. **Conclusion**: The false statement regarding the order of the -I effect is found in **Option 4**.

### Final Answer:
The false statement regarding the order of the -I effect is **Option 4**.