Find the approximate value of `25^(1//3)`

Explanation

Let `y=x^(1//3)`
Let `x=27 " and " Deltax=-2`
Now `Deltay= (x+ Deltax)^(1//3) -x^(1//3) =(25)^(1//3) -3`
`(dy)/(dx) Deltax =25^(1//3) -3`
`At x=27 ,25^(1//3) =3- 0.074 = 2.926`