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(i) Find the point on the curve 9y^(2)=x...

(i) Find the point on the curve `9y^(2)=x^(3)` where normal to the curve has non zero x -intercept and both the x intercept and y- intercept are equal.
(ii) If the tangent at (1,1) on `y^(2)=x(2-x)^(2)` meets the curve again at P, then find coordinates of P
(iii) The normal to the curve `5x^(5) -10x^(3) +x+2y+6=0` at the point P(0,-3) is tangent to the curve at some other point (s). Find those point(s)?

Text Solution

Verified by Experts

The correct Answer is:
(i) `(4,(8)/(3)) (ii) (9//4, 3//8) (iii) (1,-1),(-1,-5)`
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