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The normal drawn on the curve xy = 12 at...

The normal drawn on the curve `xy = 12` at point `(3t, 4/t)` cut the curve again at a point having parameter point `t,` then prove that `t_1 = -16/(9t^3).`

A

`(-9)/(16t^(3))`

B

`(-16)/(9t^(3))`

C

`(9)/(16t^(3))`

D

`(16)/(9t^(3))`

Text Solution

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The correct Answer is:
B
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