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Let f(x)=(1+b^2)x^2+2b x+1 and let m(b) ...

Let `f(x)=(1+b^2)x^2+2b x+1` and let `m(b)` be the minimum value of `f(x)dot` As `b` varies, the range of `m(b)` is `[0,}` b. `(0,1/2)` c. `1/2,1` d. `(0,1]`

A

`[0,1]`

B

`(0,(1)/(2)]`

C

`[(1)/(2),1]`

D

`(0,1]`

Text Solution

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The correct Answer is:
D
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