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The radius of a circle, having minimum area, which touches the curve `y=4-x^2` and the lines `y=|x|` is : `4(sqrt(2)-1)` (2) `4(sqrt(2)+1)` (3) `2(sqrt(2)+1)` (4) `2(sqrt(2)-1)`

A

`2(sqrt(2)+1)`

B

`2(sqrt(2)-1)`

C

`4(sqrt(2)-1)`

D

`(sqrt(2)+1)`

Text Solution

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The correct Answer is:
C
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