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Find area bounded by y = log(1/2) x and ...

Find area bounded by `y = log_(1/2)` x and x-axis between `x = 1` and `x = 2`

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A rough graph of `y = log_(1/2)x` is as follows
Area `= - underset(1)overset(2)intlog_(1/2)xdx = - underset(1)overset(2)intlog_(e)x.log_(1/2)edx`

`= - log_(1/2)e.[xlog_(e)x-x]_(1)^(2)=-log_(1/2)e.(2log_(e)2-2-0+1)= - log_(1/2)e.(2log_(e)2-1)`
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