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Evaluate: intx ln(1+x)dx...

Evaluate: `intx ln(1+x)dx`

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Let I `intnx ln(1+x)dx = x^(2)/2.ln(x+1)-1/2int(x^(2)-1+1)/(x+1)dx`
`x^(2)/2ln(x+1)-1/2intx^(2)/(x+1)dx=x^(2)/2ln(x+1)-1/2int(x^(2)-1+1)/(x+1)dx`
`=x^(2)/(2)ln(x+1)-1/2int((x^(2)-1)/(x+1)+1/(x+1))dx=x^(2)/2ln(x+1)-1/2int((x-1)+1/(x+1))dx`
`=x^(2)/2ln(x+1)-1/2[x^(2)/2-x+ln|x+1|]+C`
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