intsqrt((x-1)/(x+1))dx is equal to...

`intsqrt((x-1)/(x+1))dx` is equal to

`sin^(-1)1/x+sqrt(x^(2)+1)/(x)+C`

`sqrt(x^(2)-1)/(x)+cos^(-1)1/x+C`

`sec^(-1)x-sqrt(x^(2)-1)/(x)+C`

`tan^(-1)sqrt(x^(2)-1)/(x)+C`

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The correct Answer is:

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intsqrt((x-1)/(x))dx=

`sqrt(x^2-x)+log|x-(1)/(2)+sqrt(x^2-x)|+c`

`sqrt(x^2-x)-log|x-(1)/(2)+sqrt(x^2-x)|+c`

`sqrt(x^2-x)+(1)/(2)log|x-(1)/(2)+sqrt(x^2-x)|+c`

`sqrt(x^2-x)-(1)/(2)log|x-(1)/(2)+sqrt(x^2-x)|+c`

`(2)/(3)sin^(-1)(x^(2//3))+C`

`(3)/(2)sin^(-1)(x^(2//3))+C`

`(2)/(3)sin^(-1)(x^(2//3))+C`

`sqrt(x^2+3x+2)-(1)/(4)log|x+(3)/(2)+sqrt(x^2+3x+2)|+c`

`sqrt(x^2+3x+2)+(1)/(4)log|x+(3)/(2)+sqrt(x^2+3x+2)|+c`

`sqrt(x^2+3x+2)-(1)/(2)log|x+(3)/(2)+sqrt(x^2+3x+2)|+c`

`sqrt(x^2+3x+2)+(1)/(2)log|x+(3)/(2)+sqrt(x^2+3x+2)|+c`