The value of int e^sqrtx/sqrtx(sqrtx + x...

The value of `int e^sqrtx/sqrtx(sqrtx + x) dx` is equal to

`2e^(sqrt(x))-x+1]+C`

`2e^(sqrt(x))[x-2sqrt(x)+1)]+C`

`2e^sqrt(x)[x-sqrt(x)+1]+C`

`2e^sqrt(x)(x+sqrt(x)+1)+C`

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The correct Answer is:

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intsqrtx e^(sqrtx)dx is equal to

`2sqrtx-e^(sqrtx)-4sqrt(xe^(sqrtx))+C`

`(2x-4sqrtx+4)e^(sqrtx)+C`

`(2x+4sqrtx+4)e^(sqrtx)+C`

`(1-4sqrtx)e^(sqrtx)+C`

`2sqrtx-e^sqrtx +4sqrt(xe^sqrtx)+C`

`(2x-4sqrtx+4)e^sqrtx+C`

`(2x+4sqrtx+4)e^sqrt4 +C`

`(1+4sqrtx)e^sqrtx+C`

`tan^(-1)(2e^(sqrtx))+C`

`ln((1+e^(x))/(1-e^(sqrtx)))+C`

`2tan^(-1)(e^(sqrtx))+C`

`(tan^(-1)x)e^(sqrtx)+C`