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If f(x)=[ 1+x^2 ; x<=1 ,x+1; 1< x<=2 a...

If f(x)=`[ 1+x^2 ; x<=1 ,x+1; 1< x<=2` and `g(x)=1-x ; -2<=x<=1` then define the function `fog(x)`

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Verified by Experts

The correct Answer is:
`f(g(x))=[(2-2xx^(2),x0lexle1),(2-x),-1lexlt0):}`
NA
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