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Let g(x)=1+x-[x]a n df(x)={-1, x<0 0, x=...

Let `g(x)=1+x-[x]a n df(x)={-1, x<0 0, x=0f, x >0` . Then for all `x ,f(g(x))` is equal to (where [.] represents the greatest integer function). `x` (b) `1` (c) `f(x)` (d) `g(x)`

A

`x`

B

1

C

`f(x)`

D

`g(x)`

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