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if f:[1,oo)->[2,oo) is given by f(x)=x+1...

if `f:[1,oo)->[2,oo)` is given by `f(x)=x+1/x` then `f^-1(x)` equals to : a) `(x+sqrt(x^2-4))/2` b) `x/(1+x^2)` c) `(x-sqrt(x^2-4))/2` d) `1+sqrt(x^2-4)`

A

`(x+sqrt(x^(2)-4))/2`

B

`x/(1+x^(2))`

C

`(x-sqrt(x^(2)-4))/2`

D

`1-sqrt(x^(2)-4)`

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