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Let f(x)=(ax + b )/(cx+d). Then the fof ...

Let `f(x)=(ax + b )/(cx+d)`. Then the `fof (x)=x`, provided that : `(a!=0, b!= 0, c!=0,d!=0)`

A

`d+a=0`

B

`d-a=0`

C

`a=b=c=d=1`

D

`a=b=1`

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