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The domain of the function f(x)=log(1//2...

The domain of the function `f(x)=log_(1//2)(-log_(2)(1+1/(root(4)(x)))-1)` is:

A

`0ltxlt1`

B

`0ltxle1`

C

`xge1`

D

null set

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AI Generated Solution

The correct Answer is:
To find the domain of the function \( f(x) = \log_{1/2}(-\log_{2}(1 + \frac{1}{\sqrt[4]{x}}) - 1) \), we need to ensure that the expression inside the logarithm is greater than zero. Let's go through the steps: ### Step 1: Set up the inequality We start with the condition that the argument of the logarithm must be greater than zero: \[ -\log_{2}(1 + \frac{1}{\sqrt[4]{x}}) - 1 > 0 \] ### Step 2: Rearranging the inequality Rearranging the inequality gives: \[ -\log_{2}(1 + \frac{1}{\sqrt[4]{x}}) > 1 \] This can be rewritten as: \[ \log_{2}(1 + \frac{1}{\sqrt[4]{x}}) < -1 \] ### Step 3: Exponentiating both sides Using the property of logarithms, we can convert the logarithmic inequality to an exponential form: \[ 1 + \frac{1}{\sqrt[4]{x}} < 2^{-1} \] This simplifies to: \[ 1 + \frac{1}{\sqrt[4]{x}} < \frac{1}{2} \] ### Step 4: Isolate the term involving \( x \) Now, isolate the term involving \( x \): \[ \frac{1}{\sqrt[4]{x}} < \frac{1}{2} - 1 \] This simplifies to: \[ \frac{1}{\sqrt[4]{x}} < -\frac{1}{2} \] ### Step 5: Analyze the inequality The left side, \( \frac{1}{\sqrt[4]{x}} \), is always positive for \( x > 0 \). However, the right side is negative. Therefore, there are no values of \( x \) that satisfy this inequality. ### Conclusion Since there are no values of \( x \) that can satisfy the inequality, the domain of the function \( f(x) \) is the empty set. Thus, the domain of the function is: \[ \text{Domain} = \emptyset \]

To find the domain of the function \( f(x) = \log_{1/2}(-\log_{2}(1 + \frac{1}{\sqrt[4]{x}}) - 1) \), we need to ensure that the expression inside the logarithm is greater than zero. Let's go through the steps: ### Step 1: Set up the inequality We start with the condition that the argument of the logarithm must be greater than zero: \[ -\log_{2}(1 + \frac{1}{\sqrt[4]{x}}) - 1 > 0 \] ...
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