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Let g(x) be a function defined on [-1,1]...

Let g(x) be a function defined on [-1,1]. If the area of the equilateral triangle with two of its vertices at `(0,0)` and `(x,g(x))` is `sqrt(3)/4`.then the function g(x) is:

A

`g(x)=+-sqrt((1-x^(2)))`

B

`g(x)=sqrt((1-x^(2)))`

C

`g(x)=-sqrt((1-x^(2)))`

D

`g(x)=sqrt((1+x^(2)))`

Text Solution

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The correct Answer is:
B, C

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