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An alternating voltage E=200sqrt(2) sin ...

An alternating voltage `E=200sqrt(2) sin (100 t)V` is connected to a `1 muF` capacitor through an ac ammeter (it reads rms value). What will be the reading of he ammeter?

Text Solution

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Comparing `E=200sqrt2 sin (100t) with E=E_(0) sin omega t ` we find that.
`E_(0) =200sqrt2V and omega=100(rad//s)`
`"So", X_(C)=(1)/(omegaC)=(1)/(100xx10^(-6))=10^(4)Omega`
And as ac instruments reads rms value. The readin of ammeter will be,
`I_("rms")=(E_(rms))/(X_(c))=(E_(0))/(sqrt2X_(c))["as" E_(rms)=(E_(0))/(sqrt2)]`
`i.e. I_(rms)=(200sqrt2)/(sqrt2xx10^(4))=200mA`
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