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A (9)/(100pi) H inductor and a 12ohm res...

A `(9)/(100pi)` H inductor and a 12ohm resitance are connected in series to a 225V, 50Hz ac source. Calculate the current in the circuit and the phase angle betweent the current and the source voltage.

Text Solution

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`"Here" X_(L)=omegaL=2pif L=2pixx50xx(9)/(100pi)=9Omega`
`"So", Z=sqrt(R^(2)+X_(L)^(2))=sqrt(12^(@)+9^(2))=15Omega`
`"So" (a)I=(V)/(Z)=(225)/(15)=15A`
`and (b) phi=tan^(-1)((X_(L))/(R))=tan^(-1)((9)/(12))=tan^(-1)3//4=37^(@)`
i.e. the current will lag the applied voltage by `37^(@)` in phase.
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