Home
Class 12
PHYSICS
The peak value of an alternating emf E g...

The peak value of an alternating emf E given by
`E=(E_0) cos omega t`
is 10V and frequency is 50 Hz. At time `t=(1//600)s` the instantaneous value of emf is

A

10volt

B

`5sqrt3"volt"`

C

5volt

D

1volt

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    RESONANCE|Exercise SECTION F|7 Videos
  • ALTERNATING CURRENT

    RESONANCE|Exercise PART-III: Match the column|2 Videos
  • ALTERNATING CURRENT

    RESONANCE|Exercise SECTION E:|6 Videos
  • ATOMIC PHYSICS

    RESONANCE|Exercise Advanved level problems|17 Videos

Similar Questions

Explore conceptually related problems

The peak value of an alternating emf E given by E=(E_0) cos omega t is 10V and freqency is 50 Hz. At time t=(1//600)s the instantaneous value of emf is

An alternating e.m.f. is given by E=10 cos omega t . If the frequency is 50 Hz, then at time t=(1/600)s the instantaneous value of e.m.f. is

.The peak value of an alternating e.m.f. which is given by E=E_(0) coswt is 10 volts and its frequency is 50Hz .At time t=(1)/(600) s,the instantaneous e.m.f.is

The r.m.s value of alternating e.m.f. is

The peak value of alternating e.m.f. in a generator is given by e_(0) =

The value of alternating emf E in the given circuit will be

An alternating emf given by V = V_(0) sin omegat has peak value 10 volt and freguency 50 Hz The instantaneous emf at .

The value of alternating e.m.f. is e = 500 sin 100pit , then the frequency of this potential in Hz is –

The peak value of an alternating voltage applied to a 50 omega resistance is 10V. Find the rms current. If the voltage frequency is 100 Hz, write the equation for the instantaneous current.