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The rms value of the saw-tooth voltage o...

The `rms` value of the saw-tooth voltage of peak value `V_(0)` from `t=0` to `t=2T` as shown in figure is `V_(0)/sqrtx`.Find the value of `x`.

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Knowledge Check

  • Rms value of the saw-tooth voltage of peak value V_(0) as shown in-

    A
    `(V_(0))/(2)`
    B
    `(V_(0))/(sqrt(2))`
    C
    `(V_(0))/(3)`
    D
    `(V_(0))/(sqrt(3))`

  • The average value for the saw-tooth voltage of peak value of V_(0) over half the cycle as shown in figure is

    A
    `(V_(0))/(sqrt(3))`
    B
    `(V_(0))/(sqrt(2))`
    C
    `(2V_(0))/(3)`
    D
    `(V_(0))/(3)`

  • In the circuit shown in figure, Voltage V_(0) is

    A
    `11.7` volt
    B
    `11.3` volt
    C
    `0`
    D
    None

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