Home
Class 12
PHYSICS
The instantaneous voltages at three term...

The instantaneous voltages at three terminals marked X, Y and Z are given by
`V_(X)=V_(0)sin omegat, V_(Y)=V_(0)sin (omegat=(2pi)/(3))and V_(z)=V_(0)sin (omegat=(4pi)/(3))`
An ideal voltmeter is configured to read runs value of the potential difference between its terminals. is connected between points X and Y and then between Y and Z. The reading the voltmeter will be

A

`V_(X)=V_(0) sin omegat, V_(gamma)=V_(0)sin (omegat+(2pi)/(3))and V_(Z)=V_(0)sin (omegat+(4pi)/(3))`

B

`V_(XY)^(rms)=V_(0)sqrt((3)/(2))`

C

`V_(YZ)^(rms)=V_(0)sqrt((1)/(2))`

D

indpependent of the choice of the two terminals

Text Solution

Verified by Experts

The correct Answer is:
A, C
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    RESONANCE|Exercise PART-II|6 Videos

  • ALTERNATING CURRENT

    RESONANCE|Exercise HIGH LEVEL PROBLEMS|11 Videos

  • ALTERNATING CURRENT

    RESONANCE|Exercise PART-IV Comprehension|11 Videos

  • ATOMIC PHYSICS

    RESONANCE|Exercise Advanved level problems|17 Videos

Similar Questions

Explore conceptually related problems

The instantaneous voltages at three terminals marked X, Y and Z are given by [ " "V_(x)=V_(0)sinomegat , " "V_(Y)=V_(0)sin(omegat+(2pi)/3) and " "V_(Z)=V_(0)sin(omegat+(4pi)/3) An ideal voltmeter is configured to read rms value of the potential difference between its terminals. It is connected between points X and Y and then between Y and Z. The reading(s) of the voltmeter will be

In the circuit shown in the Figure, the voltage across resistance R, box A and box B are represented as v_(R)=vsin(omegat),v_(A)=sqrt(2)Vsin(omegat+(pi)/(4))and v_(B)=vsin(omegat+(pi)/(2)) Find the phase difference between current and the applied voltage.

A, B and C are voltmeters of resistances R, 1.5R and 3R respectively. When some potential difference is applied between x and y the voltmeter readings are V_A, V _B and V_C, then

Three travelling waves are superimposed. The equations of the wave are y_(!)=A_(0) sin (kx-omegat), y_(2)=3 sqrt(2) A_(0) sin (kx-omegat+phi) and y_(3)=4 A_(0) cos (kx-omegat) find the value of phi ("given "0 le phi le pi//2) if the phase difference between the resultant wave and first wave is pi//4

A voltmeter reads the potential difference across the terminals of an old battery as 1.40 V , while a potentiometer reads its voltage to be 1.55 V . The voltmeter resistance is 280 Omega .

An Ac voltage V=V_0 sin 100t is applied to the circuit, the phase difference between current and voltage is found to be pi/4 , then .

The voltage over a cycle varies as V=V_(0)sin omega t for 0 le t le (pi)/(omega) =-V_(0)sin omega t for (pi)/(omega)le t le (2pi)/(omega) The average value of the voltage one cycle is

What is the power dissipation in an AC circuit in which voltage and current are given by V = 300 sin (omegat +(pi)/(2)) and I = 5 sin omegat ?