Five identical capacitor paltes, each of area A, are arranged such that adjacent plates are at a distance d apart, the plates are connected to a source of emf V as shown in the figure

The charge on plate 1 is ………..and on plate 4 is.............

Options

A. `(in_(0)A)/(d),(-2 in_(0)A)/(d)`
B. `(in_(0)AV)/(d),(-2in_(0)AV)/(d)`
C. `(-in_(0)AV)/(d), (-3in_(0)AV)/(d)`
D. `(in_(0)AV)/(d), (-4in_(0)AV)/(d)`

Answer

B

Explanation

by equivalent circuit diagram Charge on first plate Q = CV
`Q=(in_(0)AV)/(d)`
Charge on fourth plate Q = C(-V) `Q=(-in_(0)AV)/(d)`
As plate 4 is repeated twice, hence charge on 4 will be Q''=2Q'
`Q"=-(2in_(0)AV)/(d)`
Hence the correct answer will be (B).