A capacitor is connected to a 36 V battery through a resistance of `10 Omega`. It is found that the potential difference across the capacitor rises to 4.0 V in `1 mu s.` Find the capacitance of the capacitor. (Given :`ln^(3)=1.0986, ln^(2)=0.693`)

Answer

`(10^(-7))/(In (9/8)) F=0.846 mu F`