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A capacitor of capacitance 200mu F is c...

A capacitor of capacitance `200mu F` is connected across a battery of emf 10.0 V through a resistance of `40 k Omega` for 16.0 s. The battery is then replaced by a thick wire. What will be the charge on the capacitor 16.0 s after the battery is disconnected ? (Given : `e^(-1)=0.135`)

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The correct Answer is:
`q=20xx10^(-4)(1-e^(-2))e^(-2)=233.55 mu C`
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RESONANCE-CAPACITANCE-Exercise - 1
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  12. Consider the situation shown in figure .The width of each plate is b.T...

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  16. Positive charge q is given to each plate of a parallel plate air capac...

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