The area of parallel plates of an air capacitor is `0.2 m^(2)` and the distance between them is `0.01m` The potential difference between the plates, the potential difference between the plates is `3000 V`. When a `0.01 m` thick sheet of an insulating material is placed between the plates, the potential difference decrease to 1000 volt. Determine (i) capacitance of capacitance before placing the sheet (ii) charge on each plate (iii) dielectric constant of material (iv) capacitanc after placing the insulator (v) absoulate permittivity of the dielectric.

Answer

(i)`20 in_(0)=180 pF " " (ii) 5.4 xx 10^(-7)C`
`(iii) 540 pF " " (iv) 3`
`(v) 27xx10^(-12)C^(2)N^(-1)m^(-2) " " (vi) 3xx10^(5)V//m`
`(vii) 1xx10^(5) V//m`