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The capacitance of a parallel plate capa...

The capacitance of a parallel plate capacitor with plate area `A` and separation `d` is `C`. The space between the plates in filled with two wedges of dielectric constants `K_(1)` and `K_(2)` respectively. Find the capacitance of resulting capacitor.

Text Solution

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The correct Answer is:
`C_(R)=(CK_(1)K_(2))/(K_(2)-K_(1))l n (K_(2))/(K_(1)) "where " C=(in_(0)A)/(d)`
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