The dimensions of a conductor of specific resistance p are shown. Find the resistance of the conductor across AB, CD and EF.

Answer

`R_(AB)=(pc)/(ab),R_(CD)=(pb)/(ac),R_(EF)=(pa)/(bc)`

Explanation

For a condition
`R=(pl)/A=("Re sistivity"xx"length")/("Area of cross section")`
`R_(AB)=(pc)/(ab),R_(CD)=(pb)/(ac),R_(EF)=(pa)/(bc)`