The resistance of a thin silver wire is `1,0 omega" at" 20^underline(@)C`. The wire is placed in liquid bath and its resistance rises to `1.2omega`. What is the temperature of the bath ? (Here `alpha=10^(-2)//.^(underline(o))C)`

Explanation

Here change in resistance is small so we can apply
`R=R_(0)(1+alphaDeltatheta)`
`rArr" "1.2=1xx(1+10^(-2)Deltatheta)" "rArr" "Deltatheta=20^(underline(o))C`
`rArr" "theta-20=20 rArrtheta=40^(underline(o))C`