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A conducting wire has resistance of 10 O...

A conducting wire has resistance of `10 Omega` at `0^@C` and `alpha` is `(1/273)^@C^(-1)`, then determine its resistance at `273^@C`

Text Solution

Verified by Experts

In such a problem, term `alpha Delta `T will have a larger value so could not be used directtly in `R=R_(0)(1+alphaDeltaT)`. We need to go for basics as
As we know that `alpha=(dR)/(RdT)`
`rArrint(dR)/R=intalphadTrArrlnR_(2)/R_(1)=alpha(T_(2)-T_(1))`
`rArrR_(2)=R_(1)e^(alpha(T_(2)-T_(1)))rARrR_(2)=10e^(1)`
`rArrR_(2)=10eOmega`
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