Find the current in the circuit (a) & (b) and also determine percentage error in measurrng the current through an ammeter.

Explanation

`"In "A I=10/2=5A`
`"In "BI=(10)/(2.5)=4A`
`"Percentge error is ="(i-i)/ixx100=20%`
Here we see that due to ammeter the current has reduced. A good ammeter has very low resistance as compared with other resistores, so that due to its presence in the circuit the current is not affectod.