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Find the reading of ammeter ? Is this th...

Find the reading of ammeter ? Is this the current through `6 Omega` ?

Text Solution

Verified by Experts

`R_("eq")=(3xx6)/(3+6)+1=3Omega`
`"Current through battery I"=18/3=6A`
So, current through ammeter `=6xx6/9=4A`
No, it is not the current through the `6 Omega` resistor.
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