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The current density in a wire is 10A//cm...

The current density in a wire is `10A//cm^(2)` and the electric field in the wire is 5 V/cm. If p = resistivity of material, `sigma`= conductivity of the material then (in SI unit)

A

`rho=5xx10^(-3)`

B

`rho=200`

C

`sigma=5xx10^(-3)`

D

`sigma=200`

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The correct Answer is:
A, D
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RESONANCE-CURRENT ELECTRICITY-Exercise-2 (Part-3)
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