Rod `PQ` of length `2l` is rotating about one end `P` in a uniform magnetic field `B` which is perpendicular to the plane of rotation of the rod . Point `M` is the mid- point of the rod. Find the induced emf between `M` and `Q` if the potential between `P` and `Q` is `100 V`.

Explanation

`E_(MQ)+E_(PM)=E_(PQ)`
`E_(PM)=(Bwl^(2))/(2)=100`
`E_(MQ)+(B omega((l)/(2))^(2))/(2)=(B omegal^(2))/(2)implies E_(MQ)=(3)/(8)B omegal^(2)=(3)/(4)xx100V=75V`