Home
Class 12
PHYSICS
A rod PQ of length l is rotating about e...

A rod `PQ` of length `l` is rotating about end `P`, with an angular velocity `omega`. Due to electrifugal forceed the free electrons in the rod move toward the end `Q` and an emf is created. Find the induced emf.

Text Solution

Verified by Experts

The accumulation of free electrons will create an electric field which will finally belance the centrifugal forces and a steady state will be reached. In the steady state `m_(e)omega(2)x=eE`.
`V_(P)-V_(0)=int_(x-0)^(x=l) barE.d barx=int_(0)^(l)(m_(e)omega^(2)x)/(e )dx=(m_(e)omega^(2)l^(2))/(2e)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A rod is rotating with angular velocity omega about axis AB. Find costheta .

A rod of mass 2 kg ad length 2 m is rotating about its one end O wth an angular velocity omega=4rad//s . Find angular momentum of the rod about the axis rotation.

When a rod of length l is rotated with angular velocity of omega in a perpendicular field of induction B , about one end , the emf across its ends is

A uniform rod of length l is spinning with an angular velocity omega=2v/l while its centre of mass moves with a velocity v . Find the velocity of the end of the rod.

A metal rod length l rotates about on end with a uniform angular velocity omega . A uniform magnetic field vecB exists in the direction of the axis of rotation. Calculate the emf induced between the ends of the rod. Neglect the centripetal force acting on the free electrons as they money in circular paths.

(a) A metal rod of length L rotates about an end with a uniform angular velocity omega . A uniform magnetic field B exists in the direction of the axis of rotation. Calculate the emf induced between the ends of the rod. Neglect the centripetal force acting on the free electrons as they move in circular paths. (b) A rod of length L rotates with a small but uniform angular velocity omega about its perpendicular bisector. A uniform magnetic field B exists parallel to the axis of rotation. Find the potential difference (i) between the centre of rod and one end and (ii) between the two ends of the rod.

Rod PQ of length 2l is rotating about one end P in a uniform magnetic field B which is perpendicular to the plane of rotation of the rod . Point M is the mid- point of the rod. Find the induced emf between M and Q if the potential between P and Q is 100 V .