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A straight wire with a resistance of r p...

A straight wire with a resistance of `r` per unit length is bent to form an angle `2alpha`.A rod of the same wire perpendicular to the angle bisector (of `2alpha`) forms a closed triangular loop.This loop is placed in a uniform magnetic field of induction `B`.Calculate the current in the wires when the rod moves at a costant speed `V`.

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The correct Answer is:
`(BV sin alpha)//r(1+sin alpha)`
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