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Two capacitors of capacitances 2C and C ...

Two capacitors of capacitances `2C` and `C` are connected in series with an inductor of inductance `L`. Initially, capacitors have charge such that `V_B - V_A = 4V_0` and `V_C- V_D = V_0`. Initial current in the circuit is zero. Find

(a) maximum current that will flow in the circuit,
(b) potential difference across each capacitor at that instant,
(c) equation of current flowing towards left in the inductor.

Text Solution

Verified by Experts

The correct Answer is:
`(a) I_("max")=(sqrt((6C)/(L)))v_(0):" " (b) 3v_(0),3v_(0);" " (c) i=I_("max")sin omegat; omega=(sqrt(3)/(2LC))`
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