Home
Class 12
PHYSICS
A straight rod of length L extends from ...

A straight rod of length `L` extends from `x=a` to `x=L+a`. Find the gravitational force exerts on a point mass `m` at `x=0` is (if the linear density of rod`mu=A+Bx^(2)`)

A

`Gm(a(1/alpha-1/(alpha+l))+bl)`

B

`(Gm(a+bx^2))/l^2`

C

`Gm(alpha(1/a-1/(a+l)+bl)`

D

`Gm(a(1/(alpha+l)-1/alpha))+bl)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    RESONANCE|Exercise EXERCISE-2 PART-2|10 Videos
  • GRAVITATION

    RESONANCE|Exercise EXERCISE-2 PART-3|12 Videos
  • GRAVITATION

    RESONANCE|Exercise EXERCISE-1 PART-3|2 Videos
  • GEOMATRICAL OPTICS

    RESONANCE|Exercise Advance level Problems|35 Videos
  • NUCLEAR PHYSICS

    RESONANCE|Exercise Advanced level solutions|16 Videos

Similar Questions

Explore conceptually related problems

A straight of length L extends from x=a to x=L+a. the gravitational force it exerts on a point mass 'm' at x=0, if the mass per unit length of the rod is A+Bx^(2), is given by :

A straight rod of length 'l' extends from x=l to x=2l. If linear mass density of rod is mu=((mu_0)/(l^3)X^3) , then the gravitational force exerted by rod on a particle of mass m at x=0 , is

A rod of length l is pivoted about an end . Find the moment of inertia of the rod about this axis if the linear mass density of rod varies as rho = ax^(2) + b kg/m

A mass m is at a distance a from one end of a uniform rod of length l and mass M. Find the gravitational force on the mass due to tke rod.

A thin rod of mass M and length L is bent into a semicircle as shown in diagram. What is a gravitational force on a particle with mass m at the centre of curvature?

If the linear density of a rod of length L varies as lambda = A+Bx , find the position of its centre of mass .

Find the gravitatinal force of between a point mass m placed at a disance x on the prolongation of a thin rod of mass M andlength l from near end .

A thin rod of length L is bent to form a semi circle. The mass of the rod is M . What will be the gravitational potential at the centre of the circle?

A rod of length L is placed along the x-axis between x=0 and x=L. The linear mass density is lambda such that lambda=a+bx . Find the mass of the rod.

A point mass M is at a distance S from an infinitely long and thin rod of linear density D . If G is the gravitational constant then gravitational force between the point mass and the rod is