The nucleus resulting from `""_(92)U^(238)` after successive emission of two `alpha` and four `beta` -particles is

The number of protons and neutrons left in ""_(92)U^(238) after emission of an a-particle are

On decay of ""_(92)U^(238) to a stable nucleus ""_(82)Pb^(206) , the number of alpha and beta particles emitted ar

If ._92 U^238 undergoes successively 8 alpha- decays and 6 beta- decays, then resulting nucleus is.

If ._92 U^238 undergoes successively 8 alpha- decays and 6 beta- decays, then resulting nucleus is.

The neutron to proton ratio of the daughter element after a nucleides ""_(92)U^(238) loses an alpha -particle and a beta particle successively is

The isotope ._(92)U^(238) successively undergoes eight alpha -decays and six beta -decays. The resulting isotope is found to be ._(92-5y)X^(238-4x) . Find the value of ratio x//y .

""_86^222Rn goes through radioactive distintegrations by successive emissions of alpha, alpha, beta, beta , alpha , beta " and " beta particles. Then final nucleus is